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Week 1-Part 5: Dominant Strategies


April 24, 2016

Definition (Domination)

Let sis_i and sis'_i be two strategies (formally defined later, take it to mean :choice of action” ) for player ii and let SiS_{-i} be the set of all possible strategy profiles for the other players. Then we say that:

  • sis_i strictly dominates sis_{i}^{\prime} if siSi,ui(si,si)>ui(si,si)\forall s_{-i} \in S_{-i}, u_{i}\left(s_{i}, s_{-i}\right)>u_{i}\left(s_{i}^{\prime}, s_{-i}\right)

    i.e. if, for every joint set of actions the other player will take, the utility player ii gets by playing sis_i is strictly more than the utility ii gets when they play sis^\prime _i

  • sis_i very weakly dominates sis_i^\prime if siSi,ui(si,si)ui(si,si)\forall s_{-i} \in S_{-i}, u_{i}\left(s_{i}, s_{-i}\right) \geq u_{i}\left(s_{i}^{\prime}, s_{-i}\right)

    i.e. if, for every joint set of actions the other player will take, the utility player ii gets by playing sis_i is greater than or equal to more than the utility ii gets when they play sis^\prime _i

When a strategy dominates another strategy, you don’t need to think about what the other agents will do in order to decide that you would prefer to play sis_i instead of sis^\prime_i. If one strategy dominates all others, we say it is dominant. If this is the case, then sis_i is better than everything else (i.e. it is the best thing to do). If you have a dominant strategy, you don’t need to worry about what the other agents will do, you can always play the dominant strategy.

Claim: A strategy profile consisting of dominant strategies for every player must be a Nash equilibrium. This must be true because since all the strategies are dominant, no agent will want to change their strategy. Furthermore, an equilibrium in a strictly dominant strategy must be unique. If not, it is not strictly dominant.

Example (Prisoner’s Dilemma)

Consider the following matrix:

CDC1,14,0D0,43,3\begin{array}{c|c|c} & C & D \\ \hline C & -1,-1 & -4,0 \\ \hline D & 0,-4 & -3,-3 \\ \hline\end{array}

Claim: Player 1 has a dominant strategy, which is playing DD. We can prove this using a case analysis:

  • Suppose Player 2 chooses CC. Then, Player 1 faces a choice of getting a payoff of -1 or a payoff of 0. Since 0>1, player 1’s best response is to play DD.
  • Suppose Player 2 chooses DD. Then, Player 1 faces a choice of getting a payoff of -4 or a payoff of -3. Since -3>-4, player 1’s best response is to play DD.

Therefore, regardless to what Player 2 does, PLayer 1’s best response is to strictly choose DD. Therefore DD is a dominant strategy. The same case analysis applies to Player 2 (symmetric)


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